If the left is a function call, it will still error out because you can't assign... | Hacker News

Hacker Newsnew | past | comments | ask | show | jobs | submit

		cbhl on March 1, 2014 \| parent \| context \| favorite \| on: A brief history of one line fixes If the left is a function call, it will still error out because you can't assign to it. If you're doing `if (var1 == var2)` then yoda expressions won't save you, however.

koenigdavidmj on March 2, 2014 [–]

Also, in C++ you can assign to the return value of a function returning a reference.

Guidelines | FAQ | Lists | API | Security | Legal | Apply to YC | Contact